(2 sin2 x − 1)(3 tan2 x − 1) = 0

2sin²x - 1 = 0 means sinx = ±1/√2  Picture a right-angled triangle with sides 1, 1 and √2. The first-quadrant angle whose sin is 1/√2 is therefore 45°.  The second quadrant value is 135°.  The third and fourth quadrants have negative values, so here x is 225° and 315°

3tan²x - 1 = 0 means tanx = ±1/√3  Picture a right-angled triangle with sides 1, √3 and 2.  This triangle has angles 30° and 60°, with tan 30° = 1/√3. In the third quadrant tan is also positive, so tan 220° is also 1/√3.

In the second and fourth quadrants tan is negative so tan 150° and tan 330° are equal to -1/√3 .

I think that the answer is sin2=0. Hope it helps.