+33661 I assume this is meant to be $$\frac{20xy^2-4xy}{4xy}$$ and you want to simplfy it.
The product 4xy is common to both terms in the numerator so you can write the expression as $$\frac{4xy(5y-1)}{4xy}$$
The 4xy terms on the top and bottom cancel, so you are left with $$5y-1$$
+33661 I assume this is meant to be $$\frac{20xy^2-4xy}{4xy}$$ and you want to simplfy it.
The product 4xy is common to both terms in the numerator so you can write the expression as $$\frac{4xy(5y-1)}{4xy}$$
The 4xy terms on the top and bottom cancel, so you are left with $$5y-1$$
