27x=9x+1
Hello Guest!
\(27x=9x+1 \) |\(-9x\)
\(27x-9x=1 \)
\(18x=1\) | /18
\(x=\frac{1}{18}\)
proof
\(27\cdot \frac{1}{18}=9\cdot \frac{1}{18}+1\\ \frac{27}{18}=\frac{9}{18}+\frac{18}{18}\\ \frac{27}{18}=\frac{27}{18}\)
!
(33x) = 32(x+1) equate the exponents
3x = 2x+2
x = 2
Firt line SHOULD read
27x = 9x+1
\(27^x=9^{x+1}\)
\((3^3)^x=(3^2)^{x+1}\\ 3^{3x}=3^{2(x+1)}\\ 3x=2x+2\\ \color{blue}x=2\)