2√(3x + 7) - 2 = x + 3
Add 2 to both sides:
2√(3x + 7) = x + 5
Divide both sides by 2:
√(3x + 7) = (x + 5)/2
Square both sides:
3x + 7 = (x2 + 10x + 25)/4
Multiply both sides by 4:
12x + 28 = x2 + 10x + 25
Subtract 12x + 28 from both sides:
0 = x2 - 2x - 3
Factor:
0 = (x - 3)(x + 1)
Solve:
x = 3 or x = -1
2√(3x + 7) - 2 = x + 3
Add 2 to both sides:
2√(3x + 7) = x + 5
Divide both sides by 2:
√(3x + 7) = (x + 5)/2
Square both sides:
3x + 7 = (x2 + 10x + 25)/4
Multiply both sides by 4:
12x + 28 = x2 + 10x + 25
Subtract 12x + 28 from both sides:
0 = x2 - 2x - 3
Factor:
0 = (x - 3)(x + 1)
Solve:
x = 3 or x = -1