2xi(i-4i^2)

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2xi(i-4i^2)

Guest Feb 23, 2015

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Best Answer

2xi(i - 4i²) = (2xi)(i) - (2xi)(1²) = 2xi² - 2xi³

If i = √(-1), then i² = -1 and i³ = -i:

---> 2xi² - 2xi³ = 2x(-1) - 2x(-i) = -2x + 2xi

geno3141 Feb 23, 2015

geno3141 · Answer 1 · 2015-02-23T02:03:59

2xi(i - 4i²) = (2xi)(i) - (2xi)(1²) = 2xi² - 2xi³

If i = √(-1), then i² = -1 and i³ = -i:

---> 2xi² - 2xi³ = 2x(-1) - 2x(-i) = -2x + 2xi