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3 numbers: sum of 27 product of 585

Guest Feb 27, 2017
 #1
avatar+87334 
0

Here's one possibilty.....assume all the numbers are integers...one of the numbers must be 5 because a product ending in 5 must have a factor of 5

 

Dividing 585 / 5  =  117

 

And 117  can be written as   9 * 13  .......so

 

Let

 

a = 5, b = 9, c =13

 

a + b + c  = 5 + 9 + 13 = 27

 

a*b*c  = 5 * 9 * 13  = 585

 

 

cool cool cool

CPhill  Feb 27, 2017

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