|3(x-2)+7|=6 solve for x

|3(x-2)+7|=6   simplifying within the absolute value, we have

l3x - 6 + 7l = 6

l3x + 1l = 6      because lal = a  or  l-al = a  .... this implies that either

3x + 1 = 6       or       -(3x + 1) = 6

So, solving the first equation, we have

3x + 1 = 6       subtract 1 from both sides

3x = 5             divide both sides by 3

x = 5/3

And solving the second equation we have

-(3x + 1) = 6

-3x - 1 = 6         add 1 to both sides

-3x = 7              divide both sides bt -3

x = -7/3

And there are our two solutions.......