Solve the following system:
{10 y - 3 x = 11 | (equation 1)
8 y - 2 x = 10 | (equation 2)
Subtract 2/3 × (equation 1) from equation 2:
{-(3 x) + 10 y = 11 | (equation 1)
0 x+(4 y)/3 = 8/3 | (equation 2)
Multiply equation 2 by 3/4:
{-(3 x) + 10 y = 11 | (equation 1)
0 x+y = 2 | (equation 2)
Subtract 10 × (equation 2) from equation 1:
{-(3 x)+0 y = -9 | (equation 1)
0 x+y = 2 | (equation 2)
Divide equation 1 by -3:
{x+0 y = 3 | (equation 1)
0 x+y = 2 | (equation 2)
Collect results:
Answer: |x = 3 and y = 2
