+226 3x-4y=7 Add plus 4y to both sides
3x-4y+4y=4y+7 So +4y-4y=0
3x=4y+7 Divide both side by 3
$${\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}}{{\mathtt{3}}}}$$ = $${\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}}\right)}{{\mathtt{3}}}}$$ So $${\frac{{\mathtt{3}}}{{\mathtt{3}}}}$$ cancel each other
$${\mathtt{x}} = {\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}}\right)}{{\mathtt{3}}}}$$ This is your answer, though you don't need the brackets and the multiplication sign between the 4 and the y, this is just the way the built in calculator formats it.
+226 3x-4y=7 Add plus 4y to both sides
3x-4y+4y=4y+7 So +4y-4y=0
3x=4y+7 Divide both side by 3
$${\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}}{{\mathtt{3}}}}$$ = $${\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}}\right)}{{\mathtt{3}}}}$$ So $${\frac{{\mathtt{3}}}{{\mathtt{3}}}}$$ cancel each other
$${\mathtt{x}} = {\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}}\right)}{{\mathtt{3}}}}$$ This is your answer, though you don't need the brackets and the multiplication sign between the 4 and the y, this is just the way the built in calculator formats it.
