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Two questions actually. Playing a game and trying to reverse engineer the prize pool for boss runs. 40565/105680=1529/x  and 40565/105680=638/x

 Jul 8, 2014

Best Answer 

 #2
avatar+33665 
+5

$$$$\frac{40565}{105680}=\frac{1529*0.75}{n}$$\\
means that $$n=1529*0.75*\frac{105680}{40565}$$$$

Can you take it from here?

 Jul 8, 2014
 #1
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+5

So, I am figuring the first part at .38384 meaning the 1529 is 38% of x. I am trying to figure out how to solve for the next step. Its been 20 years since I've done this type of math. Lol

Although now that I think about it, he recieved a bonus 25% for being the highest rpp done so I need to take off 25% from the 1529 and 638 first. So the actual question turns into...

40565/105680=(1529*0.75)/n

40565/105680=(638*.075)/n

This should give me the base prize pools without the bonuses... if someone can point me in the right direction on how to solve this myself I would appreciate it. Thanks.

 Jul 8, 2014
 #2
avatar+33665 
+5
Best Answer

$$$$\frac{40565}{105680}=\frac{1529*0.75}{n}$$\\
means that $$n=1529*0.75*\frac{105680}{40565}$$$$

Can you take it from here?

Alan Jul 8, 2014

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