5(4x-2)/8(2x-1)

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5(4x-2)÷8(2x-1)

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\(\dfrac{5(4x-2)}{8(2x-1)}=\dfrac{10(2x-1)}{8(2x-1)}=\dfrac{10}{8}=\dfrac 5 4\)

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Rom Oct 2, 2015

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