(5 p(q to the 3rd)/4(p to the 3rd)q)to the 2nd

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Guest Oct 14, 2014

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Best Answer

$$\\\dfrac{5pq^3}{4p^3q^2}\\\\\\
=\dfrac{5\not{p}\;q\not{q}\not{q}}{4\not{p}\;p\;p\not{q}\not{q}}\\\\\\
=\dfrac{5q}{4p^2}\\\\$$

Melody Oct 15, 2014

Melody · Answer 1 · 2014-10-15T08:56:25

$$\\\dfrac{5pq^3}{4p^3q^2}\\\\\\
=\dfrac{5\not{p}\;q\not{q}\not{q}}{4\not{p}\;p\;p\not{q}\not{q}}\\\\\\
=\dfrac{5q}{4p^2}\\\\$$

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