72=(1/2)(18)(12)sinA

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72=(1/2)(18)(12)sinA

Guest Feb 28, 2015

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Best Answer

+23254

+5

72 = (1/2)(18)(12)sin(A)

But: (1/2)(18)(12) = 108

So: 72 = 108sin(A)

Divide both sides by 108:

72/108 = sin(A)

Find the inverse sine:

sin^-1(72/108) = 41.8°

geno3141 Mar 1, 2015

1⁺⁰ Answers

+23254

+5

Best Answer

72 = (1/2)(18)(12)sin(A)

But: (1/2)(18)(12) = 108

So: 72 = 108sin(A)

Divide both sides by 108:

72/108 = sin(A)

Find the inverse sine:

sin^-1(72/108) = 41.8°

geno3141 Mar 1, 2015

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