A ball initially at rest rolls down a hill with an acceleration of 2.7 m/s^2 . If it accelerates for 6.8 s, how far will it move? Answer in units of m
u=0
a=2.7
t=6.8
find s
s=ut+1/2*at^2
you can do the substitution.
------------
Do you like these variables better?
+24 
