A card is chosen at random from a standard deck of 52 cards, and then it is replaced and another card is chosen. What is the probability that at least one of the cards is a diamond or an ace?
There are 16 cards in a deck of 52 which is an ace or a diamond or both. So that means the probability of NOT choosing an ace or a diamond or both on both turns is:
((52-16)/52)^2
(36/52)^2
(9/13)^2
81/169
This means that the probability of choosing an ace or a diamond or both on both turns is:
1 - 81/169
88/169
There are 16 cards in a deck of 52 which is an ace or a diamond or both. So that means the probability of NOT choosing an ace or a diamond or both on both turns is:
((52-16)/52)^2
(36/52)^2
(9/13)^2
81/169
This means that the probability of choosing an ace or a diamond or both on both turns is:
1 - 81/169
88/169