A dice is rolled 6 times. Find the probability of rolling no more than 2 ones (round four decimal places)
No more than two "1s" means no "1s", one 1 or two "1s"
No "1s" = (5/6)^6 = about .33489
One 1 = C(6,1)(1/6)(5/6)^5 = abouy .40187
Two "1s" = C(6,2) (1/6)^2(5/6)^4 = about .2009
So....the probability of rolling no more than 2 "1s" = .33489 + .40187 + .2009 = about .93766 or .9377 (rounded)