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A hot bowl of soup is served at a dinner party. It starts to cool according to Newton's Law of Cooling so that its temperature at time t is given by

T(t) = 53 + 150e −0.05t

where t is measured in minutes and T is measured in °F.

(a) What is the initial temperature of the soup?
(b)What is the temperature after 10 min?
(c) After how long will the temperature be 100°F?
 Jul 10, 2014

Best Answer 

 #1
avatar+33663 
+5

Soup

.
 Jul 10, 2014
 #1
avatar+33663 
+5
Best Answer

Soup

Alan Jul 10, 2014

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