A math textbook is 1 3/8 in thick. How many of these books will for in 33 in shelf?
+118724 Division is the least understood of the 4 basic operations ( + - x ÷ )
Whenever you get a problem with yucky numbers, try replacing those numbers with something more understandable.
so in this case you could change the question to
A math textbook is 2cm in thick. How many of these books will for in 10cm in shelf?
2+2+2+2+2=10 so the answer is 5 umm
10÷2=5 There you go, I had to use divide.
-------------------------------- ALSO-----------------------
You really need to know how many $$1\frac{3}{8}$$ cm books will go into a 33cm shelf. See 'will go into' is also a big clue. It screams Divide!
$$33\div 1\frac{3}{8} = \frac{33}{1}\div \frac{11}{8}=
\frac{33}{1}\times \frac{8}{11}=3\times 8=24$$
24 books just like CPhill got.
+130547 First....we are dividing the width of the shelf by the width of each book .... this gives ....
33 /(1 +3/8) =
(33 / 1) / (11 / 8) Invert the fraction in the denominator and multiply by the fraction in the numerator
(33/1) * (8/11) cross-cancel the "33" with the "11"
(3/1) * (8/1) = 24 books
+118724 Division is the least understood of the 4 basic operations ( + - x ÷ )
Whenever you get a problem with yucky numbers, try replacing those numbers with something more understandable.
so in this case you could change the question to
A math textbook is 2cm in thick. How many of these books will for in 10cm in shelf?
2+2+2+2+2=10 so the answer is 5 umm
10÷2=5 There you go, I had to use divide.
-------------------------------- ALSO-----------------------
You really need to know how many $$1\frac{3}{8}$$ cm books will go into a 33cm shelf. See 'will go into' is also a big clue. It screams Divide!
$$33\div 1\frac{3}{8} = \frac{33}{1}\div \frac{11}{8}=
\frac{33}{1}\times \frac{8}{11}=3\times 8=24$$
24 books just like CPhill got.
