+0  
 
0
6366
3
avatar

A parabola opening up or down has vertex (0,4) and passes through ( - 10, - 1). Write its equation in vertex form.

 May 13, 2014

Best Answer 

 #1
avatar+130555 
+5

Ok...so we have this........

y = ax2 + 4      ....... and we need to find "a"

So we have

-1 = a(-10)2 + 4

-5 = a (100)

(-1/20) = a      .......  So we have ..........

y = (-1/20)(x- 0)2 + 4   or just  (-1/20)x2 + 4

Note that this parabola opens downward...That makes sense since the vertex is above the x axis and the parabola passes through a point below the x axis.

 May 13, 2014
 #1
avatar+130555 
+5
Best Answer

Ok...so we have this........

y = ax2 + 4      ....... and we need to find "a"

So we have

-1 = a(-10)2 + 4

-5 = a (100)

(-1/20) = a      .......  So we have ..........

y = (-1/20)(x- 0)2 + 4   or just  (-1/20)x2 + 4

Note that this parabola opens downward...That makes sense since the vertex is above the x axis and the parabola passes through a point below the x axis.

CPhill May 13, 2014
 #2
avatar
0

It's right if b= 0 !

 May 13, 2014
 #3
avatar+118725 
0

Opening up or down implies that the axis of symmetry is parallel to the y axis.

CPhill's  answer is the only possible answer!

 May 14, 2014

1 Online Users