A parabola opening up or down has vertex (0,4) and passes through ( - 10, - 1). Write its equation in vertex form.
Ok...so we have this........
y = ax2 + 4 ....... and we need to find "a"
So we have
-1 = a(-10)2 + 4
-5 = a (100)
(-1/20) = a ....... So we have ..........
y = (-1/20)(x- 0)2 + 4 or just (-1/20)x2 + 4
Note that this parabola opens downward...That makes sense since the vertex is above the x axis and the parabola passes through a point below the x axis.
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Ok...so we have this........
y = ax2 + 4 ....... and we need to find "a"
So we have
-1 = a(-10)2 + 4
-5 = a (100)
(-1/20) = a ....... So we have ..........
y = (-1/20)(x- 0)2 + 4 or just (-1/20)x2 + 4
Note that this parabola opens downward...That makes sense since the vertex is above the x axis and the parabola passes through a point below the x axis.
![]()