The graph of the equation $y =ax^2 + bx + c$, where $a$, $b$, and $c$ are constants, is a parabola with axis of symmetry $x = -3.$ Find $\frac{b}{a}$.
y=(x+3)^2
y = x^2 + 6x + 9
6/1 = 6
I hope this helped. :)))
=^._.^=
+195 
