A shop keeper had 4 handbag which were of the same price He sold 3of them at 40% more than the cost price He sold the forth handbag at the cost price .he received $260 altogether. Find the cost of each handbag
+3454 Well, let's write out an equation for this word problem. He sold one of them at cost price, (N) and the other 3 at 40% more than cost price [ 3(n+.40n) ] and the total was 260.
N+3(N+.40N)= 260
N+3N+1.2N=260
5.2N=260
N = 50
The original cost of each handbag was $50!
