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(a) When rebuilding her car's engine, a physics major must exert 550 N of force to insert a oiled steel piston into a steel cylinder at a constant velocity. (Assume the coefficient of kinetic friction is 0.03.) What is the normal force between the piston and cylinder?
 N
(b) What force would she have to exert if the steel parts are dry, so that the coefficient of friction is 0.3?
 N

physics
 Nov 2, 2014

Best Answer 

 #1
avatar+33665 
+5

The resistive force is given by μ, where μ is coefficient of friction and M is normal force.  For constant velocity there must be no net force acting on the piston, so μ*M = applied force

 

(a)   0.03*M = 550.     M = 550/0.03   $${\mathtt{M}} = {\frac{{\mathtt{550}}}{{\mathtt{0.03}}}} \Rightarrow {\mathtt{M}} = {\mathtt{18\,333.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$ or M ≈ 18333N

 

(b) I'll leave you to do this.

.

 Nov 3, 2014
 #1
avatar+33665 
+5
Best Answer

The resistive force is given by μ, where μ is coefficient of friction and M is normal force.  For constant velocity there must be no net force acting on the piston, so μ*M = applied force

 

(a)   0.03*M = 550.     M = 550/0.03   $${\mathtt{M}} = {\frac{{\mathtt{550}}}{{\mathtt{0.03}}}} \Rightarrow {\mathtt{M}} = {\mathtt{18\,333.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$ or M ≈ 18333N

 

(b) I'll leave you to do this.

.

Alan Nov 3, 2014

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