Absolute extrema on closed interval [-1,2] of f(x)=x^2(x-3)

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What are the absolute extrema on closed interval [-1,2] of f(x)=x^2(x-3)

Guest Oct 29, 2014

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Best Answer

From the graph I can see that the maximum is f(0)=0

and minimums are

f(-1)=-4 and f(2)=-4

Melody Oct 29, 2014

Melody · Answer 1 · 2014-10-29T07:12:07

From the graph I can see that the maximum is f(0)=0

and minimums are

f(-1)=-4 and f(2)=-4