If (2x-3) is a function of 6x^3 + 59x^2 - 25x - 150, what are the remaining functions?
First, the (2x - 3) is NOT a factor. By ramaining functions, you mean remaining "factors".
Factor the following:
6 x^3+59 x^2-25 x-150
The possible rational roots of 6 x^3+59 x^2-25 x-150 are x = ±1/6, x = ±5/6, x = ±25/6, x = ±1/3, x = ±2/3, x = ±5/3, x = ±10/3, x = ±25/3, x = ±50/3, x = ±1/2, x = ±3/2, x = ±5/2, x = ±15/2, x = ±25/2, x = ±75/2, x = ±1, x = ±2, x = ±3, x = ±5, x = ±6, x = ±10, x = ±15, x = ±25, x = ±30, x = ±50, x = ±75, x = ±150. Of these, x = 5/3, x = -3/2 and x = -10 are roots. This gives 3 x-5, 2 x+3 and x+10 as all factors:
Answer: |
| (3x-5) (2x+3) (x+10)
