We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

(sqrt(-2(h+x))-sqrt(-2x))/h

How do I simplify this? Anyone who knows and can give step-by-step answers, I would really appreciate it. Thanks.

gibsonj338 Apr 21, 2018

#1**+1 **

hint: apply radical rule!

I'll post a solution later, but my answer is: \(\frac{\sqrt{2h-2x}}{h}-i \frac{\sqrt2\sqrt x}{h}\)

.tertre Apr 21, 2018

#2**+2 **

(sqrt(-2(h+x))-sqrt(-2x))/h

\(\frac{{\sqrt{-2(h+x)}-\sqrt{-2x}} }{h} \\ \frac{{\sqrt{-1}\sqrt{2(h+x)}-\sqrt{-1}\sqrt{2x}} }{h} \\ \frac{\sqrt{-1}\left[\sqrt{2(h+x)}-\sqrt{2x}\right]}{h} \\ \frac{\left[\sqrt{2h+2x}-\sqrt{2x}\;\right]\;i}{h} \\ or\\ \frac{\left[\sqrt{h+x}-\sqrt{x}\;\right]\sqrt2\;i}{h} \\ \)

the final answer really depends on what you are doing it for.

Melody Apr 21, 2018