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I'm currently stuck with my college math. i hate to do this but i need help with four questions

A. SOLVE FOR X

log(4)x+log(4)(x-15)=2

B. SOLVE FOR X

ln(x+1)=0

C. SOLVE FOR X

9^(x+1)=4

D. SOLVE FOR X

(3-2x)-4(2+x)=4x
 Dec 9, 2013
 #1
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1. = 31 over 4

2.= -1

3.= 9-4
9

4.= -1 over 2
 Dec 9, 2013
 #2
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StuckWithMath:

I'm currently stuck with my college math. i hate to do this but i need help with four questions

A. SOLVE FOR X

log(4)x+log(4)(x-15)=2

B. SOLVE FOR X

ln(x+1)=0

C. SOLVE FOR X

9^(x+1)=4

D. SOLVE FOR X

(3-2x)-4(2+x)=4x



There is a lot of questions here.
ok I'll start with d.
(3-2x)-4(2+x)=4x
expand out the left hand side and simplify it by adding like terms.
move the 'lots of x' to the right side - do you know how to do that? (remember it is opposite so if it was +20x then you would -20x from both sides.)
lastly you divide both sides by the number in front of the x.

question C you have to take the log of both sides to solve it.
then look for an identity you can use from this web page
http://en.wikipedia.org/wiki/List_of_logarithmic_identities

question B consider this
log xy = 0
then x 0 = y
what does y have to equal?
This is an interactive web page that takes an introductory look at logs. You probably should work through it.

question A is the hardest one
log(4)x+log(4)(x-15)=2
If you mean exactly what you have written then the question is
xlog4 + (x-15)log4 = 2
You can collect the lots of log 4 on the left eg 6x + (3+1)x = (6+3+1)x This is just an example to give you a hint.
Then you can solve it like any equation. Just remember log4 is just a number.

That's enough help for starters.
Get back to me and show me what you have acheived by yourself.
 Dec 10, 2013

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