StuckWithMath: I'm currently stuck with my college math. i hate to do this but i need help with four questions
A. SOLVE FOR X
log(4)x+log(4)(x-15)=2
B. SOLVE FOR X
ln(x+1)=0
C. SOLVE FOR X
9^(x+1)=4
D. SOLVE FOR X
(3-2x)-4(2+x)=4x
There is a lot of questions here.
ok I'll start with d.
(3-2x)-4(2+x)=4x
expand out the left hand side and simplify it by adding like terms.
move the 'lots of x' to the right side - do you know how to do that? (remember it is opposite so if it was +20x then you would -20x from both sides.)
lastly you divide both sides by the number in front of the x.
question C you have to take the log of both sides to solve it.
then look for an identity you can use from this web page
http://en.wikipedia.org/wiki/List_of_logarithmic_identities
question B consider this
log
xy = 0
then x
0 = y
what does y have to equal?
This is an interactive web page that takes an introductory look at logs. You probably should work through it.
question A is the hardest one
log(4)x+log(4)(x-15)=2
If you mean exactly what you have written then the question is
xlog4 + (x-15)log4 = 2
You can collect the lots of log 4 on the left eg 6x + (3+1)x = (6+3+1)x This is just an example to give you a hint.
Then you can solve it like any equation. Just remember log4 is just a number.
That's enough help for starters.
Get back to me and show me what you have acheived by yourself.