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Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid a total of $1360, how many first class passengers were there on the trip?

 Dec 6, 2015

Best Answer 

 #1
avatar+118724 
+5

Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid a total of $1360, how many first class passengers were there on the trip?

 

F+T=52

30F+25T=1360

 

Now solve them simultaneously.  Can you do that?

 Dec 6, 2015
 #1
avatar+118724 
+5
Best Answer

Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid a total of $1360, how many first class passengers were there on the trip?

 

F+T=52

30F+25T=1360

 

Now solve them simultaneously.  Can you do that?

Melody Dec 6, 2015
 #2
avatar
+5

Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid a total of $1360, how many first class passengers were there on the trip?

 

Let the number of first class=F

Let the number of tourist class=T, then we have:

F + T=52, But,

30F + 25T=1360


Solve the following system:
{30 F+25 T = 1360 |     (equation 1)
F+T = 52 |     (equation 2)
Subtract 1/30 × (equation 1) from equation 2:
{30 F+25 T = 1360 |     (equation 1)
0 F+T/6 = 20/3 |     (equation 2)
Divide equation 1 by 5:
{6 F+5 T = 272 |     (equation 1)
0 F+T/6 = 20/3 |     (equation 2)
Multiply equation 2 by 6:
{6 F+5 T = 272 |     (equation 1)
0 F+T = 40 |     (equation 2)
Subtract 5 × (equation 2) from equation 1:
{6 F+0 T = 72 |     (equation 1)
0 F+T = 40 |     (equation 2)
Divide equation 1 by 6:
{F+0 T = 12 |     (equation 1)
0 F+T = 40 |     (equation 2)
Collect results:
Answer: |     F = 12        and            T = 40
 

 Dec 6, 2015

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