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Let p and q be the two distinct solutions to the equation x^2 - 2x - 8 = 0. What is (p+1)(p+1)?

 Sep 25, 2021
 #1
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What is (p+1)(q+1)

 

From Vieta:          p + q = - b/a      =   2

                                 pq = c/a        =   -8

 

(p+1)(q+1)   =    pq    +     p + q    +       1

                           -8    +        2       +       1   =  -5

 Sep 25, 2021
 #2
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Let p and q be the two distinct solutions to the equation x^2 - 2x - 8 = 0. What is (p+1)(p+1)?     

 

You mean (p+1)(q+1) as EP already said.   

 

Won't x2 – 2x – 8 factor to (x – 4)(x + 2)    

 

In which case    x = +4  and  x = –2   

 

So (4 + 1)(–2 + 1)  =  5 • –1  =  –5  

.

 Sep 25, 2021

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