Let p and q be the two distinct solutions to the equation x^2 - 2x - 8 = 0. What is (p+1)(p+1)?
What is (p+1)(q+1)
From Vieta: p + q = - b/a = 2
pq = c/a = -8
(p+1)(q+1) = pq + p + q + 1
-8 + 2 + 1 = -5
You mean (p+1)(q+1) as EP already said.
Won't x2 – 2x – 8 factor to (x – 4)(x + 2)
In which case x = +4 and x = –2
So (4 + 1)(–2 + 1) = 5 • –1 = –5
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