The height of an object is given by h = -16t^2 + 137t + 100 Find the two points in time when the object is 148 feet above the ground . Round your answer to the nearest hundredth of a second (two decimal places)
The object is 148 feet above the ground, so let h = 148:
\(148 = -16t^2 + 137t + 100\\ 16t^2 - 137t + 48 = 0\)
You can now use quadratic formula to solve for the two values of t.
