If c is a constant such that 9x^2 + 12x + c is equal to the square of a binomial, then what is c?
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\(9x^2 + 12x + c\)
\((u+v)^2=u^2+2uv+v^2\) first binom
\((3x+2 )^2=9x^2+12x+4\)
\( c=4\)
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