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# Algebra

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For how many real values of x is sqrt(63 - 3*sqrt(x)) an integer?

Apr 27, 2021

### 1+0 Answers

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You cannot find the square root of a negative number

So x is a positive square number.

and     $$0\le 63-3\sqrt{x} \le63$$

Now just test integer square values of x starting with x=0, then 1,4,9 etc

Apr 28, 2021