Jack and Joe leave their homes at the same time and drive toward each other. Jack drives at 80 mph, while Joe drives at 30 mph. They pass each other in 10 minutes. How far apart were Jack and Joe when they started?

Guest Jan 10, 2021

#1**+1 **

Best Answer

Jack speed = 80mph

Joe speed = 30 mph

..

travelling towards each other

so speed = 30+80 =110 mph.

let distance be x when they start.

time take = 10 minutes = 1/6 hour

..

d= r*t

d= 110*1/6

d= 18 1/3 miles.

hihihi Jan 10, 2021

#2**+1 **

Just simple kinematics,

Jack = v1 = 60 mph

Joe = v2 = 30 mph

t = 10 min = 1/6 hr

Jack Dist = (60 mph) * (1/6 hr) = 10 miles

Joe Dist = (30 mph) * (1/6 hr) = 5 miles

Total Distance Between = 15 miles

If you have trouble imagining points starting from some unknown and traveling to a mid point, just imagine it as if they started from some point then traveled away in the same manner, how far apart the would be.

Potatobird Jan 10, 2021