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If (x+y)^2 = 45 and xy=8, what is the value of (x-y)^2?

 Sep 25, 2020
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(x + y)^2 = 45

x^2 + y^2 + 2xy = 45

x^2 + y^2 + 2(8) = 45

x^2 + y^2 = 29

 

(x-y)^2 = x^2 + y^2 -2xy

[x^2 + y^2] - 2xy =

[29] -16 = 13

 Sep 25, 2020

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