+219 Let $x$ and $y$ be nonnegative real numbers. If $x + y = 25$, then find the minimum value of $6x + 3y.$
+1926 Alright. Let's first put y in terms of x.
We get \(y=25-x\).
Subbing this value back into the second equation, we get
\(3x+75\).
Since x can't be negative, the smallest possible value of x is 0.
When x is 0, we have \(3(0)+75=75\)
So 75 is our final answer.
Thanks! :)
