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The equation y = -16t^2 + 28t + 144 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 144 feet from the ground. In how many seconds will the ball reach a height of 150 feet?  Round your answer to the nearest tenth of a second.

 Apr 9, 2022
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150 = -16t^2 + 28t + 144

-16t^2 + 28t - 6  = 0                 Use quadratic formula to find the t values...one will be on the way up and one will be on the way back down.

              a = -16      b=28    c = -6

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 Apr 9, 2022

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