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Let r and s be the roots of 3x^2+4x+12 = x^2 - 5x + 7. Find r^2+s^2.

 Jan 14, 2022
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Find r^2+s^2.

 

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\(3x^2+4x+12 = x^2 - 5x + 7\\ 2x^2+9x+5=0\\ x^2+4.5x+2.5=0\\ x=-2.25\pm \sqrt{5.0625-2.5}\)

\(r^2=14.8285\\ s^2=0.4215\)

\(r^2+s^2=15.25\)

laugh  !

 Jan 14, 2022

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