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Compute 1^2/(1.3) + 2^2/(3.5) + 3^2/(5.7) + 4^2/(7.9) +............+ 500^2/(999.1001).

 Jul 2, 2020
 #1
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I took the "." in the denominators to mean "times" or "*" : if that is the case, then your sequence sums up to:

 

sumfor(n, 1, 500, (n^2 / (4*n^2 - 1))=125,250 / 1001 

 Jul 2, 2020
 #2
avatar+25543 
+2

Compute

\(S = 1^2/(1.3) + 2^2/(3.5) + 3^2/(5.7) + 4^2/(7.9) +............+ 500^2/(999.1001)\)

 

My answer see here: https://web2.0calc.com/questions/summing-up#r2

 

laugh

 Jul 2, 2020
edited by heureka  Jul 2, 2020
edited by heureka  Jul 2, 2020

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