Compute 1^2/(1.3) + 2^2/(3.5) + 3^2/(5.7) + 4^2/(7.9) +............+ 500^2/(999.1001).
I took the "." in the denominators to mean "times" or "*" : if that is the case, then your sequence sums up to:
sumfor(n, 1, 500, (n^2 / (4*n^2 - 1))=125,250 / 1001
+26367 Compute
\(S = 1^2/(1.3) + 2^2/(3.5) + 3^2/(5.7) + 4^2/(7.9) +............+ 500^2/(999.1001)\)
My answer see here: https://web2.0calc.com/questions/summing-up#r2
