algebraic equation

0

368

3

Solve 64^x = 16^(x−1)

Guest Aug 14, 2020

0 users composing answers..

2⁺⁰ Answers

+1

(2⁶)^x = (2⁴)^x-1 now equate the exponents

6x = 4x-4 and solve for 'x'

Guest Aug 14, 2020

+1

No....it IS correct.

Guest Aug 15, 2020

2 Online Users