algebraic equation

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Solve 64^x = 16^(x−1)

Guest Aug 14, 2020

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2⁺⁰ Answers

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(2⁶)^x = (2⁴)^x-1 now equate the exponents

6x = 4x-4 and solve for 'x'

Guest Aug 14, 2020

+1

No....it IS correct.

Guest Aug 15, 2020

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