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Solve 64^x = 16^(x−1)

 Aug 14, 2020
 #1
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(26)x = (24)x-1         now equate the exponents

 

6x = 4x-4     and solve for 'x'

 Aug 14, 2020
 #3
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No....it IS correct.

Guest Aug 15, 2020

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