+0  
 
0
618
7
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4^x-4^-x=2

 Nov 2, 2016
 #2
avatar+12531 
0

4^x-4^-x=2

laugh

 Nov 2, 2016
 #4
avatar+37099 
0

Hey Omi67.....when I substitute your answer into the equation I get  -2    NOT   2  ......Hmmmmmm

ElectricPavlov  Nov 2, 2016
 #5
avatar+37099 
0

Hey Omi67.....when I substitute your answer into the equation I get  -2    NOT   2  ......Hmmmmmm

 

I question this step(s)

Substitution  4x = u

u^2 - 2u -1 = 0                 u^2 would be 16x^2   NOT     4^(2x)         right???

ElectricPavlov  Nov 2, 2016
 #3
avatar
0

No thats wrong im a student i would know cool

 Nov 2, 2016
 #6
avatar+129839 
0

4x + 4-x = 2

 

4x + 4-x - 2 = 0 

 

4x + 1/4x - 2 = 0     multiply through by 4x

 

42x - 2*4x + 1  = 0        let 4x = u

 

u^2 - 2u + 1 =  0   factor

 

(u - 1)^2  = 0      take the square root of both sides

 

u - 1  = 0

 

u = 1    so

 

4x = 1      which implies that x  = 0

 

Check....    40 + 4-0  = 40 + 40  =   1 + 1  = 2

 

 

cool cool cool

 Nov 2, 2016
 #7
avatar
0

OK......I still disagree with the answers we have so far.  I couldn't figure out how to do this MATHEMAICALLY, so I graphed it at Desmos.    The only place where the graph = 0 is at   + .6358

 

x= .6358         

 

At x = 0   you  would have    4^0 - 1/(4^0) = 1-1 = 0     not   =   2

 

At x = -.6358   you wind up with  -2   not   2

 

Answer  x=.6358        (Actually if you use Omi's answer as a POSITIVE  .635776652  you will get the right answer)

 

 

~ep

 Nov 8, 2016

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