AP Physics problem

I do not understand how you got to $sin(\Theta)=1.33sin(\Theta)/(-0.1135188)$; however, this is how I would sove this equation.

$1.33\times sin(25) = 1.5\times sin(\Theta)$

$1.33\times -0.132351750098 ≈ 1.5\times sin(\Theta)$

$-0.17602782763034 ≈ 1.5\times sin(\Theta)$

$\frac{-0.17602782763034}{1.5} ≈ \frac{1.5\times sin(\Theta)}{1.5}$

$\frac{-0.17602782763034}{1.5} ≈ \frac{1\times sin(\Theta)}{1}$

$\frac{-0.17602782763034}{1.5} ≈ 1\times sin(\Theta)$

$\frac{-0.17602782763034}{1.5} ≈ sin(\Theta)$

$-0.1173518850868933 ≈ sin(\Theta)$

${sin}^{-1}(-0.1173518850868933) ≈ {sin}^{-1}[sin(\Theta)]$

$-0.11762291934 ≈\Theta$

$\Theta≈-0.11762291934$

If (1.33)sin(25) = (1.5)sin(theta), what is theta?

1.33 x 0.42261826..... = 1.5sin(theta)

0.5620823.... = 1.5sin(theta)   divide both sides by 1.5

Sin(theta) =0.5620823 / 1.5

Sin(theta) = 0.37472152541.....

Theta = Sin^-1(0.37472152541)

Theta = 22 Degrees.