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# Area and Parameter

+4
936
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+1832

How Can I Find The Area And The Parameter of the Yellow Segment !

Dec 3, 2016

#6
+32762
+10

If the result is wanted in terms of d rather than theta then the following relationship can be used:

theta = cos-1(1 - 8d/D + 8d^2/D^2)

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Dec 4, 2016

#1
+115412
+10

Hi 315,

I don't know what you mean by paremeter       , and I assume the black dot is the centre,

Height of the triangle is  $$\frac{D}{2}-d = \frac{D-2d}{2}$$

$$sec \frac{\theta}{2}=r\div \frac{D-2d}{2}\\ ( \frac{D-2d}{2})sec \frac{\theta}{2}=r\\ r=( \frac{D-2d}{2})sec \frac{\theta}{2}\\$$

assuming that theta is in radians:

\begin{align}\\Area&=\frac{\theta}{2\pi}\times\pi r^2-\frac{1}{2}r^2sin\theta\\~\\ &=\frac{\theta r^2}{2}-\frac{1}{2}r^2sin\theta\\~\\ &=\frac{ r^2}{2}(\theta-sin\theta)\\~\\ &=\frac{\left [\frac{D-2d}{2}\;sec\frac{\theta}{2}\right]^2}{2}(\theta-sin\theta)\\~\\ &=\frac{(D-2d)^2\;sec^2\left(\frac{\theta}{2}\right)(\theta-sin\theta)}{8}\quad units^2\\~\\ \end{align}

*

Dec 3, 2016
#2
+1832
+5

Great !!!!

I ment circumference by  perimeter

and I typed  perimeter wrong

sorry for that

Dec 3, 2016
#3
+121064
+10

Here's an alternative approach :

Area of whole sector   = (1/2)r^2 * θ

Area of triangle within the sector   =  (1/2)r^2 sin θ

Yellow area    =   Area of whole secor  -  Area of triangle within the sector  =

(1/2)r^2 * θ   - (1/2)r^2 sin θ   =

(1/2)r^2  [ θ -  sin θ ]

Perimeter  of yellow area   =

√ [ 2r^2  - 2r^2 cos θ]  +  r θ   =

r √ [2 - 2 cos θ ]  + r θ  =

r  [  √ [2 - 2 cos θ ]  +  θ  ]

Dec 3, 2016
#5
+32762
+10

The area simplifies to A = (D^2/8)(theta - sin(theta))

The perimeter of the yellow segment is D(theta/2 + sin(theta/2)).    The chord length can be found using either the cosine rule or the sine rule.

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Dec 4, 2016
#6
+32762
+10

If the result is wanted in terms of d rather than theta then the following relationship can be used:

theta = cos-1(1 - 8d/D + 8d^2/D^2)

.

Alan  Dec 4, 2016
#7
+1832
+5

that is amazing !

thank's alot CPhill & Alan

Dec 4, 2016