Assuming the sodium bicarbonate solution is a 1M solution, calculate the volume of concentrated HCl required to acidity contents of a test tube. The concentrated HCl has a concentration of 85.5 mL/mol
NaHCO3 molarity= 1M=1 mol/1000 mL
Volume of NaHCO3 used= 1 mol/1000 mL * 1 mL
mol of NaHCO3 = 1x10^-3 mol
