4/5(1)-2(2)+3/6-5(3)/8-6(3) is equal to -903/40 then -22.575
bakit naging -903/40 ang equal niya then ung nadivide na naging -22.575
+118723 $${\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{1}}\right){\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right){\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right)}{{\mathtt{8}}}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right) = {\mathtt{\,-\,}}{\frac{{\mathtt{903}}}{{\mathtt{40}}}} = -{\mathtt{22.575}}$$
so far this is true.
I think this question is in Filipino.
why did he then -903/40 the equal ung nadivide became -22.575
so I think you want to know why this is true.
kaya sa tingin ko nais mong malaman kung bakit ito ay totoo.
arithmetic must be done in a set order of operation.
It is sometimes referred to as BODMAS or PEDMAS.
[Anyway brackets must be dealt with first], [then exponents (or power Ofs)] then [multiply and divide are equally important] and lastly [addition and subtraction are equally imprortant]
$$\left\{{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{1}}\right)\right\}{\mathtt{\,-\,}}\left\{{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right)\right\}{\mathtt{\,\small\textbf+\,}}\left\{{\frac{{\mathtt{3}}}{{\mathtt{6}}}}\right\}{\mathtt{\,-\,}}\left\{{\frac{{\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right)}{{\mathtt{8}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{6}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right)\right\}$$
= $$\left\{{\frac{{\mathtt{4}}}{{\mathtt{5}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{4}}\right\}{\mathtt{\,\small\textbf+\,}}\left\{{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right\}{\mathtt{\,-\,}}\left\{{\frac{{\mathtt{15}}}{{\mathtt{8}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{18}}\right\}$$
= $$\left\{{\frac{{\mathtt{4}}}{{\mathtt{5}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{4}}\right\}{\mathtt{\,\small\textbf+\,}}\left\{{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right\}{\mathtt{\,-\,}}\left\{{\frac{{\mathtt{15}}}{{\mathtt{8}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{18}}\right\}$$
= $${\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,-\,}}{\mathtt{18}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{15}}}{{\mathtt{8}}}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{15}}}{{\mathtt{8}}}}$$
Now you need to get a common denominator for all those fractions. It will have to be 40
Ngayon ay kailangan mong makakuha ng isang karaniwang denominador para sa lahat ng mga fraction. Ito ay kailangang maging 40
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{20}}\right)}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{20}}\right)}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{32}}}{{\mathtt{40}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{20}}}{{\mathtt{40}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{75}}}{{\mathtt{40}}}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{32}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}{\mathtt{\,-\,}}{\mathtt{75}}\right)}{{\mathtt{40}}}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,-\,}}{\frac{{\mathtt{23}}}{{\mathtt{40}}}}$$ also equals -(22and 23/40)
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,-\,}}{\frac{{\mathtt{23}}}{{\mathtt{40}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{903}}}{{\mathtt{40}}}} = -{\mathtt{22.575}}$$
Does this help explain it?
Tulong na ito ipaliwanag ito ba?
+118723 $${\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{1}}\right){\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right){\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right)}{{\mathtt{8}}}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right) = {\mathtt{\,-\,}}{\frac{{\mathtt{903}}}{{\mathtt{40}}}} = -{\mathtt{22.575}}$$
so far this is true.
I think this question is in Filipino.
why did he then -903/40 the equal ung nadivide became -22.575
so I think you want to know why this is true.
kaya sa tingin ko nais mong malaman kung bakit ito ay totoo.
arithmetic must be done in a set order of operation.
It is sometimes referred to as BODMAS or PEDMAS.
[Anyway brackets must be dealt with first], [then exponents (or power Ofs)] then [multiply and divide are equally important] and lastly [addition and subtraction are equally imprortant]
$$\left\{{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{1}}\right)\right\}{\mathtt{\,-\,}}\left\{{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right)\right\}{\mathtt{\,\small\textbf+\,}}\left\{{\frac{{\mathtt{3}}}{{\mathtt{6}}}}\right\}{\mathtt{\,-\,}}\left\{{\frac{{\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right)}{{\mathtt{8}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{6}}{\mathtt{\,\times\,}}\left({\mathtt{3}}\right)\right\}$$
= $$\left\{{\frac{{\mathtt{4}}}{{\mathtt{5}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{4}}\right\}{\mathtt{\,\small\textbf+\,}}\left\{{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right\}{\mathtt{\,-\,}}\left\{{\frac{{\mathtt{15}}}{{\mathtt{8}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{18}}\right\}$$
= $$\left\{{\frac{{\mathtt{4}}}{{\mathtt{5}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{4}}\right\}{\mathtt{\,\small\textbf+\,}}\left\{{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right\}{\mathtt{\,-\,}}\left\{{\frac{{\mathtt{15}}}{{\mathtt{8}}}}\right\}{\mathtt{\,-\,}}\left\{{\mathtt{18}}\right\}$$
= $${\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,-\,}}{\mathtt{18}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{15}}}{{\mathtt{8}}}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{15}}}{{\mathtt{8}}}}$$
Now you need to get a common denominator for all those fractions. It will have to be 40
Ngayon ay kailangan mong makakuha ng isang karaniwang denominador para sa lahat ng mga fraction. Ito ay kailangang maging 40
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{20}}\right)}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{20}}\right)}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{32}}}{{\mathtt{40}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{20}}}{{\mathtt{40}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{75}}}{{\mathtt{40}}}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{32}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}{\mathtt{\,-\,}}{\mathtt{75}}\right)}{{\mathtt{40}}}}$$
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,-\,}}{\frac{{\mathtt{23}}}{{\mathtt{40}}}}$$ also equals -(22and 23/40)
= $${\mathtt{\,-\,}}{\mathtt{22}}{\mathtt{\,-\,}}{\frac{{\mathtt{23}}}{{\mathtt{40}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{903}}}{{\mathtt{40}}}} = -{\mathtt{22.575}}$$
Does this help explain it?
Tulong na ito ipaliwanag ito ba?
