+0  
 
0
72
1
avatar

Suppose that A, B, and C are non-zero distinct digits less than 6, and suppose we have A_6 + B_6 = C_6 and B _6 + B_6 + C_6 = AA_6. Find the three-digit number ABC. (Interpret as a base-6 number with digits A and B, not as A times B. The other expressions should be interpreted in this way as well).

 Jan 5, 2021
 #1
avatar+218 
0

A+B=C

2B+C=AA=(6A+A)=7A

A+B-C=0

2B+C-7A=0

3B-6A

With trial and error we can find A=1 B=2 C=3

 Jan 6, 2021

65 Online Users

avatar
avatar
avatar
avatar