if i have the numbers -6 5 4 2 and have to use bedmas and use all of the numbers once to get to -10 and a seperate question same instructions -22 how do i do it?
if i have the numbers -6 5 4 2 and have to use bedmas and use all of the numbers once to get to -10 ?
\(\begin{array}{|rcll|} \hline -10 &=& [5-6-4] \cdot 2 \\ -10 &=& \frac{-6-4}{2}-5 \\ \hline \end{array}\)
and a seperate question same instructions -22 how do i do it?
\(\begin{array}{|rcll|} \hline -22 &=& (5-2)\cdot (-6)-4 \\ -22 &=& \frac{(-6-5)\cdot4}{2} \\ \hline \end{array}\)
[-6 - 2 ] * 5 / 4 =
[ - 8 ] * 5 / 4 =
- 40 / 4 =
-10
-6 * 5 + 4 * 2 =
-30 + 8 =
-22
if i have the numbers -6 5 4 2 and have to use bedmas and use all of the numbers once to get to -10 ?
\(\begin{array}{|rcll|} \hline -10 &=& [5-6-4] \cdot 2 \\ -10 &=& \frac{-6-4}{2}-5 \\ \hline \end{array}\)
and a seperate question same instructions -22 how do i do it?
\(\begin{array}{|rcll|} \hline -22 &=& (5-2)\cdot (-6)-4 \\ -22 &=& \frac{(-6-5)\cdot4}{2} \\ \hline \end{array}\)