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if i have the numbers -6 5 4 2 and have to use bedmas and use all of the numbers once to get to -10 and a seperate question same instructions -22 how do i do it?

 Feb 13, 2017

Best Answer 

 #2
avatar+26388 
+10

if i have the numbers -6 5 4 2 and have to use bedmas and use all of the numbers once to get to -10 ?

\(\begin{array}{|rcll|} \hline -10 &=& [5-6-4] \cdot 2 \\ -10 &=& \frac{-6-4}{2}-5 \\ \hline \end{array}\)

 

 

and a seperate question same instructions -22 how do i do it?

\(\begin{array}{|rcll|} \hline -22 &=& (5-2)\cdot (-6)-4 \\ -22 &=& \frac{(-6-5)\cdot4}{2} \\ \hline \end{array}\)

 

laugh

 Feb 13, 2017
 #1
avatar+129840 
+5

[-6 - 2 ] * 5   / 4  =

 

[ - 8 ] * 5   / 4   =

 

- 40  / 4   =

 

-10

 

 

 

-6 * 5  +  4 * 2  =

 

-30 + 8  =

 

-22

 

 

 

cool cool cool

 Feb 13, 2017
 #2
avatar+26388 
+10
Best Answer

if i have the numbers -6 5 4 2 and have to use bedmas and use all of the numbers once to get to -10 ?

\(\begin{array}{|rcll|} \hline -10 &=& [5-6-4] \cdot 2 \\ -10 &=& \frac{-6-4}{2}-5 \\ \hline \end{array}\)

 

 

and a seperate question same instructions -22 how do i do it?

\(\begin{array}{|rcll|} \hline -22 &=& (5-2)\cdot (-6)-4 \\ -22 &=& \frac{(-6-5)\cdot4}{2} \\ \hline \end{array}\)

 

laugh

heureka Feb 13, 2017

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