+118629 Find Dy/Dx (X=pi) when y = sin(x) + sec(x).
I will change the question to: Find Dy/Dx of y = sin(x) + sec(x) at the point where x=pi
\( y = sin(x) + sec(x) \\ y = sin(x) + [ cos(x) ]^{-1}\\ y' = cos(x) +-1 [ cos(x) ]^{-2}*-sin(x)\\ y' = cos(x) +\frac{sin(x)}{cos^2(x)}\\ y'(\pi) = cos(\pi) +\frac{sin(\pi)}{cos^2(\pi)}\\ y'(\pi) = -1+\frac{0}{1}\\ y'(\pi) = -1\)
