((9.109e-31)*(1.602e-19)^4)/(72*(8.854e-12)^2*(6.626e-34)^2) where is the zero?
+118723 ((9.109e-31)*(1.602e-19)^4)/(72*(8.854e-12)^2*(6.626e-34)^2)
where is the zero?
You are dividing by e to high negative powers, these are tiny numbers and, with rounding, the calc sees them as zero.
If you want to simplify you may need to do some of it by hand.
\(\frac{(9.109e^{-31})*(1.602e^{-19})^4}{72*(8.854e^{-12})^2*(6.626e^{-34})^2}\\ =\frac{9.109e^{-31}*1.602^4e^{-76}}{72*8.854^2e^{-24}*6.626^2e^{-68}}\\ =\frac{9.109*1.602^4e^{24}e^{68}}{72*8.854^2*6.626^2*e^{31}e^{76}}\\ =\frac{9.109*1.602^4}{72*8.854^2*6.626^2*e^{15}}\\ etc\)
You are probably doing something wrong. Your bracket for the first term should be before 4th power NOT after it, to indicate that you want the product of the terms raised to the 4th power. Because the numbers you are dealing with are so small, that some calculators may NOT be able to display and hence you get errors. At any rate, here is your answer and try to compare your calculation to mine and see if you can get the same answer:
1.829862514... × 10^-109. Good luck.
