Calculator Question. Without the infnity

72 x 87.5  =  6300

The problem now is:  28 x 2^(6300)

Set the problem equal to x:  x  =  28 x 2^6300

Find the log of both sides:  log(x)  =  log(28 x 2^6300)

Now, use some properties of logs:

                                           log(x)  =  log(28) + log(2^6300)

                                           log(x)  =  log(28) + 6300log(2)

My calculator says that log(28) + 6300log(2)  =  1897.936 (approx)

                                           log(x)  =  1897.936

Changing back into exponential form:  x  =  10^(1897.936)  =  10^(1897 + 0,936)

which is:                                                x  =  10^1897 x 10^0.936

But, 10^0,936  =  8.63 (approx), so      x  =  10^1897 x 8.63  or  8.63 x 10^1897.

Do the exponent first   72 x 87.5 = 6300

 

 

This is going to be a really big number

28 x 2^6300     

 

 28 x 2^6300    the 2^6300 will come back as an error or infinity on most calculators......some may come back with a scientific notation