Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) h(p) = p − 5 p2 + 3
+130544 I assume this is :
h(p) = p − 5 p^2 + 3 if so.....take the derivative
h ' (p) = 1 - 10p
Set this to 0 and solve
1 - 10p = 0 add 10 p to both sides
1 = 10p divide both sides by 10
p = 1/10 so , we have a critical number at x = 1/10 = 0.1
The second derivative = -10.........so tthis is a max
And the point is (0.1, 3.05)
Here's the graph.......https://www.desmos.com/calculator/hvhpff2qst
+130544 I assume this is :
h(p) = p − 5 p^2 + 3 if so.....take the derivative
h ' (p) = 1 - 10p
Set this to 0 and solve
1 - 10p = 0 add 10 p to both sides
1 = 10p divide both sides by 10
p = 1/10 so , we have a critical number at x = 1/10 = 0.1
The second derivative = -10.........so tthis is a max
And the point is (0.1, 3.05)
Here's the graph.......https://www.desmos.com/calculator/hvhpff2qst
