I kind of remember how to solve this, but I'm having trouble with this one (it's been over a decade since High School).
Question:
'Solve for y. 3(2y+4) = 4(2y-1/2)'
Can anyone help break the steps down on this one for me? I know it's simple, but I'm missing a step somewhere.
Heres what I have so far; please correct me if I'm wrong:
3(2y+4) = 4(2y-1/2)
6y+12 = 8y-2
?